WEBVTT

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Take a sphere.

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Not the one in front of you,
but its cousin in a thousand dimensions.

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Almost everything you know about
the round one quietly fails up there,

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and it fails in a useful direction:

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by the end of this lecture, one fact about
where a sphere keeps its area will hand us

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a theorem about every
normed space there is.

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So start in three
dimensions, where we can look.

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Here is the unit sphere, and there,
drawn around its middle, is its equator.

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Let it turn once, so you can see
it is a ball and not a disc.

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Now mark off a band around that equator:
every point within zero point two radians

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of it, about twelve degrees
of latitude either way.

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On this sphere the band is nothing
special. It holds about twenty percent

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of the area, and you can see that: most
of the surface is out in the two caps.

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Keep that picture,
and raise the dimension.

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I cannot draw the sphere in dimension one
thousand, but I can tell you what happens

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to this same band up there:

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it swallows essentially all
of the area, and the two caps,

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which look like most of the sphere
here, hold almost nothing at all.

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The reason is a picture we can draw.

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Slice the sphere by latitude,
and ask how much area sits at each one.

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In dimension n the answer
is proportional to sine of theta,

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raised to the power n minus one.

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For our sphere that exponent is just one,
and the profile is this gentle mound.

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Now raise the exponent.

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At n equals eleven the mound sharpens.

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At n around fifty it is a spike,
standing on the equator.

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The area has nowhere else to go: any
latitude away from the equator has sine

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less than one, and a number below one,
raised to the fiftieth power, is nothing.

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Here are the guarantees,
for the very same band.

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On our sphere, dimension two,
it holds about twenty percent.

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By dimension one hundred it already
holds at least seventy two percent.

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By dimension one thousand,

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at least ninety nine point
nine nine nine nine nine percent.

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And by ten thousand, everything
except one part in ten to the eighty six.

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A band you would barely notice
on a globe is, up there, the whole sphere.

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That is concentration of measure,
and two questions come with it.

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Why the equator, of all places,
and what guarantees those numbers?

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Keep one eye on where this is heading:

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the same phenomenon will,
at the end, buy Dvoretzky's theorem.

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But first the why, and the why
is an inequality about caps.

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A cap is the sphere's own disc.

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Pick a point x zero, and take everything
within spherical distance R of it.

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There it is, poured around the pole.

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Let it turn, so you can see the cap lying
on the surface, and there is its formula.

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Now grow it.

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Take any set A and fatten it by epsilon:
everything within distance epsilon of A.

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That is the epsilon extension,

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written A sub epsilon, and for a cap
it means the cap plus this collar.

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Growing a set costs area,
and the bill is paid along the boundary:

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the longer the edge,
the more the collar adds.

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So here is Levy's question.

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Among all sets of one fixed area, which
shape, when you fatten it by epsilon,

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grows the least?

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Watch what happens to a bad candidate.

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Here is the same total area, split
into two half-size caps, one at each pole.

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Nothing about the area changed.

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What changed is the edge:

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this set has two boundary circles
where the single cap had one.

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Now fatten both sides by the same epsilon.

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The single cap grows one collar.

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The split set grows two,

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and two collars around two
circles is more new area than one.

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Same area in, more area out:
splitting was a bad trade.

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And that is the pattern in general.

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Wiggly sets, stretched
sets, scattered sets:

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at a fixed area, every one of them carries
at least as much boundary as the cap,

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and grows at least as fast.

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The cap is the minimizer.

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Say it precisely.

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If A and the cap C cover the same
fraction of the sphere, then for every

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positive epsilon, the extension of A is
at least as big as the extension of C.

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That is Levy's spherical
isoperimetric inequality,

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and it is the engine
under everything that follows.

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One more reading before we use it.

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The cap is solving the same
problem the disc solves in the plane

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and the ball solves in space:

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least boundary for the area enclosed.

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On the sphere, least
boundary becomes least growth.

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Now let us spend it.

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Here is the payoff move, and it is short.

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Take any set A covering
exactly half the sphere:

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half is where a set
and its complement balance,

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and it is the case that powers everything.

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Which cap has measure one half?

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The one of radius pi over two:

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a hemisphere.

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So the hemisphere is the shape to beat.

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Let it turn once,

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so that blue reads as half of a surface
rather than as a lid laid across one.

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Fatten the hemisphere
by epsilon and you get this:

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everything above the equator, plus a
collar of angular width epsilon below it.

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By the isoperimetric inequality, whatever

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A actually was, its extension covers at
least as much of the sphere as this does.

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So what does the grown hemisphere miss?

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Only this: the cap of radius pi over two
minus epsilon, around the opposite pole.

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Call it B. The extension covers one minus
the measure of B, and everything now rides

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on how small B is.

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And B is exactly the kind
of region the spike killed.

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Every point of it sits at latitude
at least epsilon away from the equator,

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where the sine to the n minus
one profile has already collapsed.

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Integrate that profile and the measure
of B comes out at most a constant times e

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to the minus c n epsilon squared.

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Put the chain together.

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Any set of measure one half,

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grown by epsilon, covers all of the sphere
except an exponentially small remainder.

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The constants C and c are universal:

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they depend on nothing, not
the dimension, not the set, not epsilon.

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That is the concentration inequality.

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How small is exponentially small?

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Let me plot the escaping mass,
e to the minus n epsilon squared,

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against the dimension.

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Here it is for epsilon equal to zero
point two, and above it, decaying slower,

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the thinner margin zero point one.

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Now ride the steep one.

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At n around fifty the escaping
mass is already near a tenth.

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By one hundred and fifty it
is a quarter of one percent,

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and off the right edge, in dimension one
thousand, it is ten to the minus eighteen.

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And compare the two curves:

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halving epsilon quarters the exponent, so
the thin margin decays four times slower.

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The square on epsilon is real.

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This behavior earned the spheres a title.

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A sequence of spaces satisfying
exactly this bound, uniformly in n,

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is called a normal Levy family,
and the spheres are the founding example.

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The name matters
because the mechanism travels:

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any family with the bound
inherits everything we do next.

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Concentration so far is about sets.

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The version that gets
used is about functions.

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Take any real function f on the sphere
that is Lipschitz with constant one,

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so it moves by at most the distance
you moved, and let M be its median:

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half the sphere sits at or below M.

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Now grow that half.

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Every point of the extension is within
epsilon of somewhere f was at most M,

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and a Lipschitz function
cannot climb faster than distance.

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So on the whole extension,
f is at most M plus epsilon,

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and the extension is nearly everything.

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Run the same argument from above,
with the set where f is at least M,

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and the mirror bound comes out.

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Put the two together:

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apart from an exception
of size at most twice the old one,

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every point of the sphere has f
within epsilon of the median.

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There it is: essentially the entire
sphere lands in this little window.

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Read that slowly, because it is strange.

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A Lipschitz function
on a high-dimensional sphere is,

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for every practical purpose, a constant.

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You may design f as cleverly
as you like; the geometry flattens it.

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Milman's insight was that this
is not a curiosity but a tool.

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Here is the tool at work,
first where we can see it.

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This is the cube, and everything

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that follows is one flat cut through
its centre, taken two different ways.

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Let it turn first, so you
know where its corners are.

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Cut it straight across,
parallel to a face.

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The knife goes in flat, like this,
and the face it leaves behind is a square.

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That much you
would have guessed without me.

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Now tilt the knife, until it stands
square to the long diagonal of the cube,

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the line joining one corner
to the corner furthest away from it.

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Same cube, same centre, different angle.

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And the face it leaves is a hexagon.

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A regular one, with six equal sides, cut
out of a body built entirely from squares.

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This is the step nobody
believes until they watch it.

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So turn it again, and follow the rim.

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It crosses six of the cube's twelve edges,

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and it crosses every one
of them at its midpoint.

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Six midpoints, six equal sides.

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Now lay the two sections
flat and measure them.

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Draw the biggest circle
that fits inside each one,

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and the smallest that wraps around it.

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For the square, the inner circle
has radius one and the outer reaches

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the corners at root two, so the outer is
forty one percent bigger than the inner.

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The hexagon is measurably rounder.

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Its inner circle is the larger
of the two, while its outer circle

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is the same root two, because its corners
are still edge midpoints of the same cube.

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The ratio drops to two over root
three, about one point one five.

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Same cube, better direction,

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and the section has forgotten
most of the cube's corners.

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In dimension n the same cube has central
sections round to within any tolerance you

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name, and, more surprisingly,
you do not have to hunt for the direction.

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The norm of the cube, like any norm,
is a Lipschitz function on the sphere,

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so it concentrates at its median.

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On a random subspace of the right
dimension it is nearly constant,

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and nearly constant is nearly round.

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That is Dvoretzky's theorem,

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in the sharp form Milman proved
with exactly this concentration.

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For every tolerance epsilon
there is a constant c of epsilon,

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and every n-dimensional normed space,
no matter how jagged its unit ball,

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contains a subspace
of dimension at least c

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of epsilon times log n on which the norm
is within one plus epsilon of Euclidean.

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And the proof
is this lecture run in reverse.

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Caps grow slowest, so sets

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of half measure grow to everything, so
Lipschitz functions sit at their medians,

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so norms are constant on random
subspaces, so round sections exist.

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One inequality about the oldest shape
on the sphere, pushed four steps,

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reaches every norm in every dimension.

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Log n is small, and that is honest:

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the cube itself shows you cannot
do better than logarithmic in general.

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But it is not zero,
and that is the miracle.

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In high dimension,
roundness is not the exception.

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It is what is left when there
is nowhere else for the measure to go.